Answer :
[tex](\frac{2}{3}x-1)+(\frac{3}{4}x+7)[/tex]
we can remove the parenthesis
[tex]\frac{2}{3}x-1+\frac{3}{4}x+7[/tex]group the expression with X and the numbers, then operate
[tex]\begin{gathered} (\frac{2}{3}+\frac{3}{4})x+(-1+7) \\ \\ (\frac{(4\times2)+(3\times3)}{3\times4})x+6 \\ \\ (\frac{8+9}{12})x+6 \\ \\ \frac{17}{12}x+6 \end{gathered}[/tex]we can represent the fraction as a mixed number because the numerato is greatr than the denominator
[tex]\frac{17}{12}\longrightarrow1\frac{5}{12}[/tex]so the final expression is
[tex]1\frac{5}{12}x+6[/tex]then the right option is the third