Answer :
SOLUTION
To solve this we will find the Z score for the distribution, we will use
[tex]\begin{gathered} Z=\frac{x-\mu}{\sigma} \\ where\text{ Z = standard score } \\ x=\text{ observed value = 67.2} \\ \mu=\text{ mean of the sample = 67.82} \\ \sigma=\text{ standard deviation = 2.06} \end{gathered}[/tex]Putting the values into the equation we have
[tex]\begin{gathered} Z=\frac{67.2-67.82}{2.06} \\ Z=\frac{-0.62}{2.06} \\ Z=-0.30097 \end{gathered}[/tex]Using the Zscore calculator, we have
[tex]P\left(xHence the answer is 0.382 to three decimal places