Answer :
Step 1:
Write the equation
[tex]9x^{22}\text{ - 24x + 16 = 0}[/tex]Step 2:
Write the quadratic equation formula
[tex]\begin{gathered} ax^2\text{ + bx + c = 0} \\ \text{x = }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}[/tex]Step 3:
a = 9, b = -24 and c = 16
[tex]\begin{gathered} \text{x = }\frac{-(-24)\text{ }\pm\sqrt[]{(-24)^2-4\times9\times16}}{2\times9} \\ \text{x = }\frac{24\pm\sqrt[]{576\text{ - 576}}}{18} \\ \text{x = }\frac{24\text{ }\pm\text{ }\sqrt[\square]{0}}{18} \\ \text{x = }\frac{\text{24 }\pm\text{ 0}}{18} \\ \text{x = }\frac{24-0}{18}\text{ or }\frac{24\text{ + 0}}{2} \\ \text{x = }\frac{4}{3}\text{ twice} \end{gathered}[/tex]Final answer
C. One repeated real-number solution