ANSWER and EXPLANATION
We want to draw the free body diagram of the block being held against the wall.
There are four forces acting on the block:
1. Force from the push
2. Normal force
3. Gravitational force/Weight
4. Frictional force
The free-body diagram is shown below:
where m = mass of the block
Fr = Frictional force
N = Normal force
Fp = Force from the push
Fg = Gravitational force/Weight
Since the block is in equilibrium, the net force in both horizontal and vertical directions must be 0.
Therefore, we have:
[tex]\begin{gathered} F_{\text{hor}}=N-F_p=0 \\ \text{F}_{\text{ver}}=F_r-F_g=0 \end{gathered}[/tex]As we can see, the magnitude of the Normal force will be equal to the magnitude of the force from the push and the magnitude of the Frictional force will be equal to the magnitude of the Gravitational force.
[tex]\begin{gathered} N=F_p \\ F_r=F_g \end{gathered}[/tex]We cannot calculate some of the values because the mass of the block and the coefficient of static friction are not given, but we have that:
[tex]\begin{gathered} F_p=10N \\ \Rightarrow N=F_p=10N \end{gathered}[/tex]