Question:
Solution:
If we need to calculate the sum of squares of n consecutive natural numbers, the formula is:
[tex]\sum ^n_{k\mathop=1}k^2\text{ = }\frac{n(n+1)(2n+1)}{6}[/tex]
the above formula can be proved by applying mathematical induction. Now, if we apply this formula, we get the solution:
[tex]\sum ^6_{k\mathop=1}k^2\text{ = }\frac{6(6+1)(2(6)+1)}{6}=91[/tex]
so that, we can conclude that the correct answer is:
[tex]91[/tex]
