Find the value of x in the givenright triangle.12x = [?]62°хEnter your answer as a decimal rounded to thenearest tenth.

Given:
Angle =62 degrees.
Adjacent side=x and Hypotenuse=12.
Consider the cosine formula
[tex]\cos \theta=\frac{Adjacent\text{ side}}{\text{Hypotenuse}}[/tex]Substitute Angle =62 degrees, Adjacent side=xm and Hypotenuse=12, we get
[tex]\cos 62^o=\frac{x}{12}[/tex][tex]12\times\cos 62^o=x[/tex][tex]12\times0.4695=x[/tex][tex]x=5.6[/tex]Hence the value of x is 5.6 units.