Answer:
Explanation:
We start by writing the dissociation equation to yield hydrogen and hydroxide ion
We have that as:
[tex]HCl\text{ + H}_2O\text{ }\rightleftarrows\text{ H}_3O^+\text{ + Cl}^-[/tex]
We have been told that the dissociation is 100% complete.
What this means is that the concentration of the acid is the concentration of the hydrogen ion
Thus, we have it that:
a)
[tex][H^+]\text{ = 0.00010 M}[/tex]
B) Mathematically:
[tex][H^+][OH^-]\text{ = 10}^{-14}[/tex]
We proceed to substitute for the concentration of the hydrogen ion:
[tex]\begin{gathered} 0.0001\text{ }\times\text{ \lbrack OH}^-]\text{ = 10}^{-14} \\ \\ [OH^-]\text{ = }\frac{10^{-14}}{0.0001} \\ \\ [OH^-]\text{ = 1 }\times\text{ 10}^{-10}\text{ M} \end{gathered}[/tex]
c) Mathematically:
[tex]\begin{gathered} pH\text{ = -log\lbrack H}^+] \\ pH\text{ = -log\lparen0.0001\rparen} \\ pH\text{ = 4} \end{gathered}[/tex]
d) Mathematically:
[tex]\begin{gathered} pH\text{ +}pOH\text{ = 14} \\ pOH\text{ = 14 - pH} \\ pOH\text{ = 14-4} \\ pOH\text{ = 10} \end{gathered}[/tex]
