Given 2 matrices A and B
[tex]A=\begin{bmatrix}{25} & {25} & {} \\ {0} & {-5} & {} \\ & {} & \end{bmatrix}\text{ and B=}\begin{bmatrix}{8} & {3} & \\ {3} & {0} & \\ & {} & {}\end{bmatrix}[/tex]
To find -3B+1/5A,
[tex]\begin{gathered} -3B+\frac{1}{5}A=-3\begin{bmatrix}{8} & {3} & \\ {3} & {0} & {} \\ {} & {} & \end{bmatrix}+\frac{1}{5}\begin{bmatrix}{25} & {25} & {} \\ {0} & {-5} & {} \\ & {} & \end{bmatrix} \\ =\begin{bmatrix}{-24} & {-9} & \\ {-9} & {0} & {} \\ {} & {} & \end{bmatrix}+\begin{bmatrix}{\frac{25}{5}} & {\frac{25}{5}} & {} \\ {0} & {-\frac{5}{5}} & {} \\ & {} & \end{bmatrix} \\ =\begin{bmatrix}{-19} & {-4} & \\ {-9} & {-1} & {} \\ & {} & {}\end{bmatrix} \end{gathered}[/tex]
