Given:
[tex]z=2.36[/tex]
Required:
We need to find the normal curve area to the right of the z=2.36.
Explanation:
The given z-score value is 2.36.
From the p-table, we get
The area under the curve between the mean and 2.36 is 0.49086
Add 0.5 to 0.49086 to find the area right of 2.36.
[tex]0.49086+0.5=0.99086[/tex]
Multiply by 100 to find the percentage of the area.
[tex]0.99086\times100=99.086\text{ \%}[/tex][tex]0.99086\times100=99.09\text{ \%}[/tex]
Final answer:
The percentage of the area under the normal curve is to the right of z =2.36 is 99.09%.
