Solution:
When a function f(x) is stretched vertically by a factor of an integer n, it implies that the new function g(x) is n times its old function.
Thus,
[tex]g(x)=n\times f(x)[/tex]
Given a square root function, we have
[tex]f(x)=\sqrt[]{x}[/tex]
When the function is stretched by a factor of 6, let the new function be represented as G(x). This implies that
[tex]\begin{gathered} G(x)=6\times f(x) \\ =6\times\sqrt[]{x} \\ \Rightarrow G(x)=6\sqrt[]{x} \end{gathered}[/tex]
Hence, the new function G(x) will be expressed as
[tex]G(x)=6\sqrt[]{x}[/tex]
The correct option is A.
