She bought 100 tech stocks and 200 mutual fund stocks for a total of $3600.
If we let the number of tech stocks she bought be "t" and the number of mutual fund stocks be "m", we can write:
[tex]100t+200m=3600[/tex]
Erin bought 300 tech stocks and 50 mutual fund stocks for a total of $5300. We can write:
[tex]300t+50m=5300[/tex]
Using substitution Method,
we can solve for "t" in the first equation and plug it into the second equation and find "m". The steps are shown below:
[tex]\begin{gathered} 100t+200m=3600 \\ 100t=3600-200m \\ t=\frac{3600-200m}{100} \\ t=36-2m \\ ------------ \\ 300t+50m=5300 \\ 300(36-2m)+50m=5300 \\ 10800-600m+50m=5300 \\ 10800-5300=600m-50m \\ 5500=550m \\ m=\frac{5500}{550} \\ m=10 \end{gathered}[/tex]
Now, we can use this value of "m" and put it into the equation t = 36 - 2m, and find the value of "t". Shown below:
[tex]\begin{gathered} t=36-2m \\ t=36-2(10) \\ t=36-20 \\ t=16 \end{gathered}[/tex]
Hence,
The technology stock costs $16 per share
The mutual fund stock costs $10 per share
