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Answer :

Given data:

The given rate is r= 3m/s

The distance covered in 3 seconds is,

[tex]\begin{gathered} d=3(3) \\ =9 \end{gathered}[/tex]

The distance covered in 4 seconds is,

[tex]\begin{gathered} D=4(3) \\ =12 \end{gathered}[/tex]

The distance covered in 5 seconds is,

[tex]\begin{gathered} D^{\prime}=5(3) \\ =15\text{ } \end{gathered}[/tex]

The distance covered in 6 seconds is,

[tex]\begin{gathered} D^{\doubleprime}^{\prime}=6(3) \\ =18 \end{gathered}[/tex]

The table is shown below.

View image WednesdayF465593