We need to find CB using Pitagora's theorem
PB = AB/2 = 16/2 = 8
So:
[tex]\begin{gathered} CB^2=PB^2+CP^2 \\ CB^2=\text{ 8}^2\text{ + 15}^2 \\ CB^2=\text{ 64 + 225} \\ CB^2=\text{ 289} \\ \sqrt{CB^2=\text{ }\sqrt{289}} \\ CB=\text{ 17} \end{gathered}[/tex]
Now we need to find out the area of the triangle:
[tex]\begin{gathered} A=\text{ }\frac{bxh}{2} \\ A=\frac{16x15}{2} \\ A=\text{ }\frac{240}{2} \\ A=\text{ 120} \end{gathered}[/tex]
The area of the triangle is 120 m^2.
The answer is B. 120m^2.
