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A 14-kg medicine ball is thrown at a velocity of 5m/s to a 73-kg person who is at rest on ice. The person catches the ball and subsequently slides with the ball across the ice. What is the speed of the person and ball after the collision?

Answer :

We will have the following:

First, we will solve using the conservation of momentum:

[tex]\begin{gathered} (14kg)(5m/s)+(73kg)(0m/s)=(14kg+73kg)v \\ \\ \Rightarrow70N\ast m=87kg\ast v\Rightarrow v=\frac{70kg\ast m/s}{87kg} \\ \\ \Rightarrow v=\frac{70}{87}m/s\Rightarrow v\approx0.8m/s \end{gathered}[/tex]

So, the final velocity will be approximately 0.8 m/s.

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