Given:
Mean = 1600
Standard deviation = 125
Given data follows standard distribution,
[tex]X\text{ \textasciitilde{}N(1600,125)}[/tex]
The probability of buyers who paid between $1600 and $1975.
[tex]\begin{gathered} P(1600Now, using the normal table,[tex]P(0So,
the percentage of buyers who paid between $1600 and $1975 is 49.87 %
