Answer :
SOLUTION
Looking at this, we have a total of four prices.
When the first price is picked, the probability becomes
[tex]\frac{1}{4}[/tex]After the first price is picked, we have 3 prices left. The probability of picking the second becomes
[tex]\frac{1}{3}[/tex]Probability of picking the 3rd becomes
[tex]\frac{1}{2}[/tex]Note that this is without replacement, hence the probability of picking the last becomes
[tex]\frac{1}{1}=1[/tex]So the require probability becomes
[tex]\begin{gathered} \frac{1}{4}\times\frac{1}{3}\times\frac{1}{2}\times1 \\ =\frac{1}{24} \end{gathered}[/tex]Hence the answer is
[tex]\frac{1}{24}[/tex]It is a dependable probability because it is a probability without replacement, since the preceding event has an effect on the probability of the next event
Hence the answer is dependable probability