Given:
The mass of steel is m = 1.5 kg
The initial temperature of the steel dish is
[tex]T_i=15^{\circ}C[/tex]
The heat supplied to the steel dish is Q = 61 kJ
The specific heat capacity of steel is c = 452 J/kg deg C
To find: The final temperature of the steel dish, T_f.
Explanation:
The formula to calculate the final temperature of the steel dish is
[tex]\begin{gathered} Q=mc(T_f-T_i) \\ T_f=\frac{Q}{mc}+T_i \end{gathered}[/tex]
Substituting the values, the final temperature of the steel dish will be
[tex]\begin{gathered} T_f=\frac{61\times10^3\text{ J}}{1.5kg\times452\frac{J}{kg^{\circ}C}\text{ }}+15 \\ =104.97^{\circ}C \end{gathered}[/tex]
Final Answer: The new temperature of the steel dish is 104.97 degrees Celsius.
