Let:
A = Rolling a number greater than 4 on both dices
The complement is:
A' = Not rolling a number greater then 4 on both dices
The probability is given by:
m/n
Where:
m = Number of favourables outcomes
n = Total number of outcomes
so:
[tex]P(A)=\frac{4}{36}=\frac{1}{9}[/tex]
The complement can be calculated as:
[tex]\begin{gathered} P(A^{\prime})=1-P(A) \\ P(A^{\prime})=1-\frac{1}{9}=\frac{8}{9}\approx0.889 \end{gathered}[/tex]
Answer:
Approximately 88.89%
