Answer :
Given:
The quadratic equation,
[tex]ax^2+bx+c=0[/tex]As the given equation has two real solution and a>0.
The solution is given by the formula,
[tex]\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{For a<0 the value for }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}\text{ will be positive and it will give the greater value.} \\ \text{ For a>0 it will give the value obtained will always be smaller.} \end{gathered}[/tex]