Answer :
[tex]\begin{gathered} \Rightarrow\frac{-3}{2v-8}+1=\frac{-7}{v-4} \\ \Rightarrow\frac{-3+2v-8}{2v-8}=\frac{-7}{v-4} \\ \Rightarrow\frac{-3+2v-8}{2(v-4)}=\frac{-7}{v-4} \\ \Rightarrow\frac{-3+2v-8}{2}=-7 \\ \Rightarrow-3+2v-8=-14 \\ \Rightarrow2v=-14+8+3 \\ \Rightarrow v=\frac{-3}{2} \end{gathered}[/tex]