Given a unit circle where the coordinate is represented by (cosθ, sinθ)
If the x coordinate is 1/2, then cos(x) = 1/2
Also, cosθ = adjancet side / hypotenuse. Therefore:
Adjacents side = 1 and hypotenuse = 2.
Now, the y missing coordinate is given by sinθ.
Where, sinθ = opposite side/ hypotenuse.
Then, we need to find the opposite side using the Pythagorean theorem, which is given by:
[tex]c^2=a^2+b^2[/tex]
Where:
c = hypotenuse
a= adjacent side
b= opposite side.
We need to solve for b, then:
[tex]b=\sqrt[]{c^2-a^2}[/tex]
Replace the values:
[tex]b=\sqrt[]{(2)^2-(1)^2}[/tex][tex]undefined[/tex]
