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A rock with a mass of 1.0 kg is at the top of a hill and has a potential energy of 50j.If the rock rolls to the bottom of the hill, what is its kinetic energy at the bottom of the hill?

Answer :

Given:

The mass of the rock is

[tex]m=1.0\text{ kg}[/tex]

The potential at the top of the hill is

[tex]PE=50\text{ J}[/tex]

To find:

If the rock rolls to the bottom of the hill, what is its kinetic energy at the bottom of the hill?

Explanation:

According to energy conservation, the kinetic energy at the bottom equals the potential energy at the top.

So, the kinetic energy at the bottom is

[tex]\begin{gathered} (KE)_{bottom}=(PE)_{top} \\ =50\text{ J} \end{gathered}[/tex]

Hence, the kinetic energy at the bottom of the hill is 50 J.

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