The following diagram shows the graph of the line:
The line passes througt (4,8) and (-12,0) so the slope must be:
[tex]m=\frac{8-0}{4-(-12)}=\frac{8}{16}=\frac{1}{2}=0.5[/tex]
And the y-intercept of the graph is at (0,6) so the equation must be:
[tex]y=\frac{1}{2}x+6[/tex]
Any line with the same slope will be parallel to line L, for example:
[tex]y=\frac{1}{2}x+2[/tex]
As shown in the graph:
