Given
[tex]a_n=6n-8[/tex]
To find: The first four terms of the sequence.
Explanation:
It is given that,
[tex]a_n=6n-8[/tex]
Then,
For n=1,
[tex]\begin{gathered} a_1=6(1)-8 \\ =6-8 \\ =-2 \end{gathered}[/tex]
For n=2,
[tex]\begin{gathered} a_2=6(2)-8 \\ =12-8 \\ =4 \end{gathered}[/tex]
For n=3,
[tex]\begin{gathered} a_3=6(3)-8 \\ =18-8 \\ =10 \end{gathered}[/tex]
For n=4,
[tex]\begin{gathered} a_4=6(4)-8 \\ =24-8 \\ =16 \end{gathered}[/tex]
Hence, the first four terms of the sequence is -2, 4, 10, 16.
