Answer:
Concept:
The formula for the probability of A given B is given below as
In this case, we will use the cardinality
[tex]\begin{gathered} P(A|B)=\frac{n(A\cap B)}{n(B)} \\ where, \\ A=charmed\text{ 5-10 worms} \\ B=raking\text{ the ground} \end{gathered}[/tex]
From the table, we will that
[tex]\begin{gathered} n(A\cap B)=8 \\ n(B)=8+4=12 \end{gathered}[/tex]
By substituting the values, we will have
[tex]\begin{gathered} P(A\lvert B)=\frac{n(A\operatorname{\cap}B)}{n(B)} \\ P(A\lvert B)=\frac{8}{12}=\frac{2}{3} \end{gathered}[/tex]
Hence,
The final answer = 2/3
