Answer:[tex]x\text{ = }\frac{-9\pm\sqrt[]{241}}{8}[/tex]
Explanations:
The given quadratic equation is:
[tex]4x^2+9x\text{ - 10 = 0}[/tex]
The quadratic formula is gven as:
[tex]\begin{gathered} \text{x = }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \end{gathered}[/tex]
From the given equation:
a = 4, b = 9, c = -10
Substitute these values into the quadratic formula:
[tex]\begin{gathered} \text{x = }\frac{-9\pm\sqrt[]{9^2-4(4)(-10)}}{2(4)} \\ x\text{ = }\frac{-9\pm\sqrt[]{81+160}}{8} \\ x\text{ = }\frac{-9\pm\sqrt[]{241}}{8} \end{gathered}[/tex]
