Given:
Length of a side for square 1 = 10 in
Length of a side for square 2 = 24 in
A square has 4 equal sides.
Since the three squares form a right triangle, to find the length of the third square, use pythogoras theorem.
We have the formula:
[tex]\begin{gathered} c^2=a^2+b^2 \\ \\ c=\sqrt[]{a^2+b^2} \end{gathered}[/tex]
where, a = 10 in
b = 24 in
We have:
[tex]\begin{gathered} c=\sqrt[]{10^2+24^2} \\ \\ c=\sqrt[]{100+576} \\ \\ c=\sqrt[]{676} \\ \\ c=26\text{ } \end{gathered}[/tex]
Therefore, the length of a side of the third square is 26 inches.
ANSWER:
B. 26 inches
