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Answer :

The circumference of a circle is computed as follows:

[tex]C=2\pi r[/tex]

Solving for r, and replacing with C = 5, we get:

[tex]\begin{gathered} 5=2\pi r \\ \frac{5}{2\pi}=r \\ 0.8m\approx r \end{gathered}[/tex]

The volume of a sphere is computed as follows:

[tex]V=\frac{4}{3}\pi r^3[/tex]

Substituting with r = 0.8, we get

[tex]\begin{gathered} V=\frac{4}{3}\pi\cdot0.8^3 \\ V\approx2.1m^3 \end{gathered}[/tex]

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