Answer :
The Slope-Intercept form of the equation of a line is:
[tex]y=mx+b[/tex]Where "m" is the slope of the line and "b" is the y-intercept.
In this case you have this equation of the line in Point-Slope form:
[tex]y-2=3\mleft(x-1\mright)[/tex]Then, in order to write it in Slope-Intercept form, you must solve for the variable "y". So you get:
[tex]\begin{gathered} y-2=(3)(x)-(1)(3) \\ y-2=3x-3 \\ y=3x-3+2 \\ y=3x-1 \end{gathered}[/tex]The answer is:
[tex]y=3x-1[/tex]