👤

justin has x nickels and y dimes, having a maximum of 28 coins worth a minimum of $2 combined. at most 8 of the coins are nickels and no more than 22 of the coins are dimes. solve this system of inequalities qraphically and determine one possible solution.

Justin Has X Nickels And Y Dimes Having A Maximum Of 28 Coins Worth A Minimum Of 2 Combined At Most 8 Of The Coins Are Nickels And No More Than 22 Of The Coins class=

Answer :

We are given that x is the number of nickels and y the number of dimes. Since there must be at maximum 28 of them, we can express this mathematically like this:

[tex]x+y\le28[/tex]

We are also told that they combine must be worth a minimum of $2, this means mathematically:

[tex]0.05x+0.1y\ge2[/tex]

Now we are told that the number of nickels is less than 8 and the number of dimes is more than 22, this can be expressed mathematically as:

[tex]\begin{gathered} x\le8 \\ y\ge22 \end{gathered}[/tex]

Therefore we have the following system of inequalities

[tex]\begin{gathered} x+y\le28,\text{ (1)} \\ 0.05x+0.1y>=2,\text{ (2)} \\ x\le8,\text{ (3)} \\ y\ge22,\text{ (4)} \end{gathered}[/tex]

The graph this inequation is the following:

The possible solutions to the inequations are located where all the colors intercept.

For example, we can take the following point:

[tex](x,y)=(5,22)[/tex]

For inequality (1)

[tex]\begin{gathered} x+y\le28 \\ 5+22\le28 \\ 27\le28 \end{gathered}[/tex]

For inequality (2)

[tex]\begin{gathered} 0.05x+0.1y\ge2 \\ 0.05(5)+0.1(22)\ge2 \\ 2.45\ge2 \end{gathered}[/tex]

Since 5<8 and 22=22 this is a solution to the inequality.

The inequalities can be rewritten as:

[tex]\begin{gathered} y\le28-x,\text{ (1)} \\ y\le\frac{2-0.05x}{0.1},\text{ (2)} \\ x\le8,\text{ (3)} \\ y>=22,\text{ (4)} \end{gathered}[/tex]

View image MalanieC189485