Answer :
1) List known values.
sample: 0.600 mol
Pressure: 1.0 atm
Temperature: 15ºC
Constant: 0.082057 L⋅atm⋅K−1⋅mol−1
List unknown values
Volume:
2) Set the equation and solve for V.
[tex]PV=\text{nRT}[/tex][tex]\frac{PV}{P}=\frac{nRT}{P}[/tex][tex]V=\frac{nRT}{P}[/tex]3) Converting to proper units.
15ºC + 273.15 = 288.15 K
4) Plug in known values.
n: 0.600 mol
R: 0.082057 L⋅atm⋅K−1⋅mol−1
T: 288.15 K
P: 1.0 atm
[tex]V=\frac{(0.600\text{mol)}(0.082057L\cdot\text{atm}\cdot K^{-1}\cdot mol^{-1})(288.15\text{ K)}}{1.0\text{ atm}}=14.18683\text{ L}[/tex]The sample will occupy a volume of 14.19 L.