Answer :
ANSWER
The mass of the sample is 72.96 grams
EXPLANATION
Given that;
The heat lost is 6008 J
The temperature drop of the sample - 19.7 degrees Celcius
The specific heat capacity of water is 4.18J/g degrees Celcius
Follow the steps below to find the mass of the sample
Step 1; Write the formula for heat energy
[tex]\begin{gathered} \text{ q = mc}\Delta T \\ \text{ Make m the subject of the formula} \\ \text{ m = }\frac{\text{ q}}{\text{ c}\Delta T} \end{gathered}[/tex]Step 2; Substitute the given data into the formula in step 1
[tex]\begin{gathered} \text{ m = }\frac{-6008}{\text{ 4.18}\times(-19.7)} \\ \\ \text{ m = }\frac{\text{ -6008}}{\text{ - 82.346}} \\ \text{ m = 72.96 grams} \end{gathered}[/tex]Therefore, the mass of the sample is 72.96 grams