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Answer :

Solution

For this case we have the following function:

[tex]h(x)=\frac{1-3x}{x-1}[/tex]

And we can find the following:

[tex]\lim _{x\to-\infty}h(x)=-3[/tex][tex]\lim _{x\to\infty}h(x)=-3[/tex]

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