Answer:
[tex]\tau_n=4.46m\cdot N[/tex]
Explanation: We need to calculate the net torque, net torque would be the sum of three torques, (1) Clockwise torque (1) Counter-clockwise torque (3) Friction torque.
[tex]\tau_n=\tau_c+\tau_{cc}+\tau_f[/tex]
These three can be calculated from the provided information as follows:
[tex]\begin{gathered} \tau=\tau_c+\tau_{cc}+\tau_f \\ \Rightarrow \\ \tau_c=(35N\times0.12m)+(18N\times0.24M)=8.52m\cdot N \\ \tau_{cc}=(28N\times0.12N)=3.36m\cdot N \\ \tau_f=0.70m\cdot N \\ \end{gathered}[/tex]
The net torque is:
[tex]\begin{gathered} \tau_n=(8.52m\cdot N-3.36m\cdot N)-(0.70m\cdot N)=4.46m\cdot N \\ \therefore\Rightarrow \\ \tau_n=4.46m\cdot N \end{gathered}[/tex]
