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Answer :

We have to use the following trigonometric identity

[tex]\sin (90-\theta)=\cos \theta[/tex]

Given that

[tex]\cos \theta=\frac{11}{15}[/tex]

We just have to substitute

[tex]\sin (90-\theta)=\cos \theta=\frac{11}{15}[/tex]

Hence, the answer is A.

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