Answer :
In this case, we'll have to carry out several steps to find the solution.
Step 01:
data:
triangle:
sides:
a = 14 cm
b = 9 cm
c = 6 cm
Step 02:
law of cosines:
[tex]b^2=a^2+c^2-2(a)(c)\text{ cos B }[/tex][tex](9\text{ cm\rparen}^2=(14\text{ cm\rparen}^2+(6\text{ cm\rparen}^2-2(14\text{ cm})(6\text{ cm})\text{ cos B }[/tex][tex]-151\text{ cm}^2=-2(14\text{ cm})(6\text{ cm})\text{ cos B }[/tex][tex]0.8988=\text{ cos B }[/tex]B = arc cos 0.8988
B = 25.99
The answer is:
B = 26°