Given
[tex]h(x)=\begin{cases}{-5|x|+7,x\leq-2} \\ {4x+3,-2
Findh(-3) , h(5) , h(-2) , h(0) , h(6)
Explanation
a) h(-3)
[tex]\begin{gathered} h(-3)=-5|x|+7 \\ h(-3)=-5|-3|+7 \\ h(-3)=-15+7 \\ h(-3)=-8 \end{gathered}[/tex]
b) h(5)
[tex]h(5)=6[/tex]
c) h(-2)
[tex]\begin{gathered} h(x)=-5|x|+7 \\ h(-2)=-5|-2|+7 \\ h(-2)=-10+7 \\ h(-2)=-3 \end{gathered}[/tex]
d) h(0)
[tex]\begin{gathered} h(x)=4x+3 \\ h(0)=4(0)+3 \\ h(0)=3 \end{gathered}[/tex]
e) h(6)
[tex]h(6)=6[/tex]
Final Answer
Therefore ,
h(-3) = -8
h(5) = 6
h(-2) = -3
h(0) = 3
h(6) =6
