Step 1:
The area of the figure = Area of the trapezium + Area of a rectangle
Step 2:
The rectangle has dimensions of 7.8m by 6m
Find the area of rectangle A
[tex]\begin{gathered} \text{Area of the rectangle = Length }\times\text{ Breadth} \\ =\text{ 6 }\times\text{ 7.8} \\ =46.8m^2 \end{gathered}[/tex]
Step 3:
Area of trapezium
[tex]\begin{gathered} \text{Area of trapezium = }\frac{1}{2}(\text{ sum of the length of parallel sides ) }\times\text{ height} \\ \text{Area of trapezium = }\frac{1}{2}(\text{ a+b ) }\times\text{ height} \\ a\text{ = 10m , b = 12m , height = 5m} \end{gathered}[/tex]
Next
Find the area of the trapezium B
[tex]\begin{gathered} \text{Area of trapezium = }\frac{1}{2}(\text{ a+b ) }\times\text{ height} \\ \text{Area of trapezium = }\frac{1}{2}(\text{ 12+10) }\times\text{ 5} \\ \text{Area of trapezium = }\frac{1}{2}(\text{22 ) }\times\text{5} \\ \text{Area of trapezium = }\frac{110}{2} \\ \text{Area of trapezium = }55m^2 \end{gathered}[/tex]
Total area = 46.8 + 55
[tex]\begin{gathered} \text{Total area = 46.8 + 55} \\ \text{Total area = 101.8 m}^2 \end{gathered}[/tex]
Final answer
[tex]\begin{gathered} \text{Area of rectangle = 46.8 m}^2 \\ \text{Area of trapezium = 55 m}^2 \\ Totalarea=101.8m^2 \end{gathered}[/tex]
