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Answer :

Solution

For this case we can find the lenght of the remaining side like this:

[tex]x=\sqrt[]{9^2-4^2}=\sqrt[]{81-16}=\sqrt[]{65}[/tex]

And we can find tan on this way:

[tex]\tan \theta=\frac{4}{\sqrt[]{65}}=\frac{4\sqrt[]{65}}{65}[/tex]

View image ArnaZ365613

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