Answer :
To answer this question, we need to use the following property of probabilities:
[tex]P(aThen, in this case we have:[tex]P(-2.61Looking at the probabilities for the z-scores in the normal table we have:[tex]\begin{gathered} P(-2.61\lt z\lt2.99)= P(z\lt2.99)- P(z\lt-2.61) \\ =0.99861-0.00453 \\ =0.99408 \end{gathered}[/tex]Therefore:
[tex]P(-2.61\lt z\lt2.99)=0.9941[/tex]