Answer:
[tex]9.33\times10^{23}atoms[/tex]
Explanations:
Given the following parameters:
Moles of Phosphorous = 0.620 moles
According to the compound, for every 2 moles of Phosphorous, there are 5 moles of Oxygen, hence the moles of oxygen contained is given as:
[tex]\begin{gathered} moles\text{ of O}=0.620\cancel{moles\text{ of P}}\times\frac{5moles\text{ of O}}{2\cancel{moles\text{ of P}}} \\ moles\text{ }of\text{ O}=1.55moles\text{ of O} \\ \end{gathered}[/tex]
According to Avogadro's constant
1 mole = 6.02 * 10^23 atoms
1.55moles of O = 1.55 * 6.02 * 10^23 atoms
1.55moles of O = 9.33 * 10^23 atoms
Hence the individual oxygen atoms contained in a sample of P2O5 that also contains 0.620 moles of P is 9.33 * 10^23 atoms
