If ABCD is dilated by a factor of 12, thecoordinate of A' would be:65C4B21-6-5-4 43 -2 -1 0-1A2♡1to34 5A' = ([?], [])

Solution
Dilation with scale factor 1/2, then multiply by 1/2. (x, y) → (1/2x, 1/2y).
The coordinate of A is
[tex](-4,-2)[/tex]Dilation with scale factor of 1/2
A'
[tex]\begin{gathered} A^{\prime}=\frac{1}{2}(-4,-2) \\ A^{\prime}=(-2,1) \end{gathered}[/tex]The final answer
[tex]A^{\prime}=(-2,-1)[/tex]