Answer :
We will find that line as follows:
*First, we replace the values in the following expression:
[tex]y-y_1=m(x-x_1)[/tex]We are given a point with x & y components and a line that has a slope of -4/3, now we replace:
[tex]y-14=-\frac{4}{3}(x-6)[/tex]Now, we solve for y:
[tex]\Rightarrow y-14=-\frac{4}{3}x+8\Rightarrow y=-\frac{4}{3}x+22[/tex]So, the equation of a line that is parallel to y = -4/3x - 1 that passes through the point (6,