Solution:
Consider the following equation for a line:
[tex]y+5\text{ = x+1}[/tex]
to find the slope of this line, we must transform this equation to the form slope-intercept:
y = mx+b
where m is the slope of the line and b is the y-intercept of the same line.
First, solve the given equation for the variable y:
[tex]\text{y = x+1-5}[/tex]
this is equivalent to:
[tex]y=x-4[/tex]
then, the slope of this line is:
[tex]1[/tex]
now, to find any point on the line, take x=0, and replace it into the equation of the given line:
[tex]y=f(0)=0-4=-4[/tex]
thus, one point on the line would be:
[tex](0,-4)[/tex]
so that, the correct answers are:
SLOPE:
[tex]1[/tex]
POINT ON THE LINE:
[tex](0,-4)[/tex]
