Given:
The charge q1 = 0.8 C
The charge q2 = -5 C
The distance between the charges is r = 5 m
Required: The magnitude of force and type of force (attraction/repulsion)
Explanation:
The magnitude of the force can be calculated by Coulomb's law
[tex]F=k\frac{|q1q2|}{r^2}[/tex]
Here, k is the electrostatic constant whose value is
[tex]k=9\times10^9\text{ Nm}^2\text{ /C}^2[/tex]
On substituting the values, the magnitude of force will be
[tex]\begin{gathered} F=9\times10^9\times\frac{0.8\times5}{(5)^2} \\ =1.44\times10^9\text{ N} \end{gathered}[/tex]
The charges are opposite in nature, thus the charges will attract.
Final Answer: The magnitude of the force is 1.44e9 N and the charges will attract.
