14) Given:
[tex](3i)(8-i)(4-6i)[/tex]
To simplify:
On simplification we get,
[tex](3i)(8-i)(4-6i)=(24i-3i^2)(4-6i)[/tex]
As we know,
[tex]i^2=-1[/tex]
We get,
[tex]\begin{gathered} =(24i-3(-1))(4-6i) \\ =(24i+3)(4-6i) \\ =96i-144i^2+12-18i \\ =96i+144+12-18i \\ =156+78i \end{gathered}[/tex]
Hence, the answer is,
[tex]156+78i[/tex]
