ksWe need to first calculate our junctions on the graph.
Firstly, she drives for 2 minutes to the store at 1 block per minute giving her total distance driven as:
[tex]2\min \times\frac{1block}{\min ute}=2blocks[/tex]
Then she stays in the same place for 4 minutes, giving us a zero gradient.
At this point, she has spent 6 minutes and covered 2 blocks
She also drives to the bank, 8 blocks from the store at 2 blocks per minute giving time spent as:
[tex]8b\text{locks }\div\text{ 2 blocks per minute = 4 minutes}[/tex]
At this point, she has driven 10 blocks and spent 10 minutes.
She spends 2 minutes thus, we have no gradient. We now have spent 12 minutes at that point.
Lastly, she drives back home 10 blocks away at the speed of 5 blocks per 3 minutes.
Therefore, time spent on the journey home:
[tex]\frac{10\min utes}{\frac{5blocks}{3\min s}}=\frac{10}{5}\times3=6\min utes[/tex]
So, at this point, we are at 18 minutes and 0 distance.
The graph: