Answer :
If each box is numbered , so that they are distinguishable , then professor can distribute the journal in 40!/(10! )⁴ ways .
In the question ,
it is given that
the professor had 40 issues of mathematics journal;
number of boxes to be packed in = 4 boxes
number of issues per box = 10 issues
since the 4 boxes are numbered ,
So , in
Box 1 , the 10 issues out of 40 can be packed in ⁴⁰C₁₀ ways .
and
for box 2 the number of issues remaining is 30
So , in Box 2 the 10 issues out of 30 can be packed in ³⁰C₁₀ ways .
for Box 3
the number of issues remaining is 20
so, in box 3 the 10 issues out of 20 can be filled in ²⁰C₁₀ ways .
for Box4
the umber of issues remaining is 10 ,
so , in box 4 the 10 issues out of 10 can be filled in ¹⁰C₁₀ ways .
The journals can be distributed in ⁴⁰C₁₀ × ³⁰C₁₀ × ²⁰C₁₀ × ¹⁰C₁₀ ways
= (40!)/(30! * 10! ) × (30!)/( 20! * 10!) × (20!)/(10! * 10!) × 1
On simplifying further , we get
= 40!/(10! )⁴ ways .
Therefore , If each box is numbered , so that they are distinguishable , then professor can distribute the journal in 40!/(10! )⁴ ways .
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