Answer :
Using the concepts of Faradays Law, we got that 294.375V is the induced E.M.F. after change in magnetic field.
The given parameters;
magnetic field strength, B₁ = 0.60 T
and magnetic field strength, B₂=-0.65T
diameter of the loop, d₂ = 6 cm
time of change, t = 120ms
The direction of the current can be determined by applying Flemings left hand rule, as the field points into the paper, the current will be point out of the paper.
The magnitude of the induced emf is calculated by applying Faradays law;
Emf= - (N×ΔФ)/Δt
Emf= - (N×(B₂-B₁)×(π×d²)/4)/120×[tex]10^{-3}[/tex]
Emf=- [(1×(-0.65-0.60))×π×(6×6)/4)]/120×[tex]10^{-3}[/tex]
Emf= [(1.25×3.14×36)]/[(4×120×[tex]10^{-3}[/tex])]
Emf= [(35.325/480)]×1000
Emf= 294.375V
Hence, the induced E.M.F after changing of magnetic field is 294.375V
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