Answer :
A sporting goods store sells tennis balls for per can when a quantity up to cans is purchased. 620 cans will maximize the transaction.
Calculating the problem:
The given parameters are:
The unit rate of 20 cans is 2.40
The unit rate of cans excess of 20 is 0.02
Let the number of cans be x.
So, the function is represented as:
f(x) = 2.40 ×20 + 0.02 × ( x - 20)
This gives:
f(x) = 48 + 0.02x - 0.4
The limit is 60.
So, we have:
60 = 48 + 0.02x - 0.4
Collect like terms:
0.02x = 60 - 48 + 0.4
0.02x = 12.4
x = [tex]\frac{12.4}{0.02}[/tex]
x = 620
Hence, 620 cans will maximize the transaction.
What's revenue for a business?
Revenue refers to the total earnings a company generates through its core operations like deals of products or services, rents on a property, recreating payments, interest on borrowings, etc. profit computations come ahead removing any charges, similar as abatements and returns.
Total earnings :
total earnings means pay for regular hours, overtime, premium pay, shift differential, retroactive pay adaptations, call- in, Saturday and Sunday decorations and tradetraining.total earnings means all stipend, payment, commission and other payment for services delivered under the worker’s pay envelope earning concurrence with the employer.
The question is incomplete. Missing part is :
A sporting goods store sells tennis balls for $2.40 per can when a quantity up to 20 cans is purchased. For each can above 20 purchased, the price per can is reduced by $0.02. with a limit of 60 cans. How many cans of tennis balls sold in one transaction will maximize the revenue for the store?
Learn more about revenue :
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